Recall that the height of an object t seconds after it begins moving when gravity is the only force acting on the object is given by h(t)=−16t2+v0t+h0,
where h(t) is given in feet, v0 is the initial velocity of the object in ft/sec, and h0 is the initial height of the object in feet.

If a ball is thrown directly upward from the top of a building with an initial velocity of 64 feet per second, and an initial height of 70 feet. What is the maximum height attained by the ball?
Your answer is
feet.