Write 1234 base 5 in powers of 5.

Step-by-step explanation:

613 = 4x125 + 113 = 4x53 + 113

Hence the first digit (reading left to right) is a 4.

The remainder is 113 so how many 25's are there in 113?

113/25 = 4 with a remainder of 13

Thus

613 = 4x125 + 4x25 + 13 = 4x53 + 4x52 + 13

Hence the second digit (reading left to right) is also a 4.

The remainder is 13 so how many 5's are there in 13?

13/5 = 2 with a remainder of 3

Thus

613 = 4x125 + 4x25 + 2x5 + 3 = 4x53 + 4x52 + 2x5 + 3

Hence the third digit (reading left to right) is a 2 and the units digit is 3. Therefore

613 written in base 5 is 4423

example

70

step-by-step explanation: