The sum of three consecutive odd integers is 237.what are the integers

let the 1st number be x

then second number is x+2

then third number is x+2+2

according to question

sum of three consecutive odd integers is 237.

hence, x+x+2+x+2+2=237

3x+6=237

3x=237-6

3x=231

x=231/3

x=77

therefore 1st integer is 77

2nd integer is 77+2=79

3rd integer is 77+2+2=81

77, 79, 81

Step-by-step explanation:

You can represent the equation as follows:

x + x + 2 + x + 4 =237

Combine like terms.

3x + 6 = 237

Subtract 6 from both sides.

3x = 231

Divide both sides by 3.

x = 77

Now, add 2 to 77 to determine the second integer.

77 + 2 = 79

Add 4 to 77 to determine the third integer.

77 + 4 = 81