8/y = 2/y-2 +1 Answer fast please.

Given equation is (8/y) = 2/(y-2) +1

=> (8/y)- 2/(y-2) = 1

=> [8(y-2)-2y]/(y-2)y = 1

=> (8y-16-2y)/(y²-2y) = 1

=> (6y-16)/(y²-2y) = 1

=> y²-2y = 6y-16

=> y²-2y -6y+16 = 0

=> y²-8y+16 = 0

The standard form is y²-8y+16 = 0.

-6

Step-by-step explanation:

8/y = 2/y - 2 + 1

8/y = 2/y - 1

8 = 2 - y

6 = -y

y = -6

answer: i think it's a

step-by-step explanation:

take it another