1. A vector starts at point ( -2, 1) and ends at point (-6, -2) what is the horizontal component of the vector? 2. A vector starts at point ( -6, 0) and ends at point (10, -4) what is the vertical component of the vector?

3. A vector starts at point ( -3, 9) and ends at point (3, -7) what is the magnitude of the vector, answer to two decimal places.

ok I guess we should I am not good I am mad so yeah

Using vector concepts, it is found that:

1. The horizontal component of the vector is 5.

2. The magnitude is of 14.87.

3. The vertical component of the vector is 2.

A vector (x,y) has x as horizontal component and y as vertical component.

The magnitude is  

Given two points, a vector is formed by the subtraction of the endpoint by the start point.

Item 1:

The horizontal component of the start is -3.

The horizontal component of the end is 2.

Thus, the horizontal component of the vector is  

Item 2:

Starts at (1,9), ends at (6,-5), thus, the coordinates are:

The magnitude is:

The magnitude is of 14.87.

Item 3:

The vertical component of the start is -10.

The vertical component of the end is -8.

Thus, the vertical component of the vector is

Step-by-step explanation:

x/3-10=8

x/3=18

x=48

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.