Mathematics, 20.10.2021 14:00, FireStorm4346

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFraction 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line? 2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17

Answers: 3

Show answers

Other questions on the subject: Mathematics

Mathematics, 20.06.2019 18:04, matius0711

Plz i want answer and i would appreciate it is is a b c or d

Answers: 1

continue

Mathematics, 21.06.2019 14:30, mathsuxdix

All per-unit concepts rely on ratios, meaning, to provide a type of measurement

Answers: 3

continue

Mathematics, 21.06.2019 16:00, hateschool5207

Identify a1 and r for the geometric sequence an= -256(-1/4) n-1

Answers: 3

continue

Mathematics, 21.06.2019 16:30, angeline310

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Answers: 2

continue

Do you know the correct answer?

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus...