The function f(t)=850(1.055)^{\frac{t}{30}}f(t)= 850(1.055)
30
t
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Mathematics, 19.10.2021 16:50, ineedhelp368
The function f(t)=850(1.055)^{\frac{t}{30}}f(t)= 850(1.055)
30
t
represents the change in a quantity over t days. What does the constant 1.055 reveal about the rate of change of the quantity?
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Answers: 1
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