Mathematics
Mathematics, 19.10.2021 02:00, TH3L0N3W0LF

AC~=DC~=, AC ~=DE (Given) AC=DC, AB=DE (Def of ~=) AC+CB = AB(Seg Add. Post.) DC+CE = DE (Seg. Add. Post.) AC+CE = DE (Subst. Prop. of=) AC+CB=DE (Subst. Prop. of=) CB=CE(Trans. Prop. of=)


AC~=DC~=, AC ~=DE (Given) AC=DC, AB=DE (Def of ~=) AC+CB = AB(Seg Add. Post.) DC+CE = DE (Seg. Add.

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AC~=DC~=, AC ~=DE (Given) AC=DC, AB=DE (Def of ~=) AC+CB = AB(Seg Add. Post.) DC+CE = DE (Seg. Add....

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