What is the y-intercept of a line perpendicular to y = kx + 6 that passes through the point (4.-3)? A: 5
B: 5/2
C: -5
D: -11

To start, any question that asks you for a line perpendicular to another, you should know that the slope of the new line will be the negative reciprocal of the slope given

In your case the opposite of 2x is

1

2

x

and then we make it negative to get

−

1

2

x

from here, you have enough information to solve the problem using point slope form. which is

y

−

y

1

=

m

(

x

−

x

1

)

now we plug in what we are given:

y

1

is 6, the slope (m) is

−

1

2

x

and

x

1

is 4.

Now, we should have

y

−

6

=

−

1

2

(

x

−

4

)

Next, we distribute the

−

1

2

(

x

−

4

)

and get

−

1

2

x

+

2

our equation at this point is now

y

−

6

=

−

1

2

x

+

2

Finally we just have to add the -6 from both sides to get

y

alone.

Our FINAL equation is

y

=

−

1

2

x

+

8

its b

Hope this helps!!

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: