β4 < x < 2
2 > x > 8
Mathematics, 18.10.2021 19:30, nettaboo4664
Solve for x: β1 < x + 3 < 5
2 < x < 8
β4 < x < 2
2 > x > 8
β4 > x > 2
Answers: 3
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Do you know the correct answer?
Solve for x: β1 < x + 3 < 5
2 < x < 8
β4 < x < 2
2 > x > 8
β4 < x < 2
2 > x > 8
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