Urn A contains 3 white and 5 black balls, and Urn B contains 2 white and 6 black balls. An experiment consists of tossing a biased coin once (P(H)=0.6) and then choosing a ball at random from one of the urns. The ball is chosen from Urn A if heads turns up and from Urn B otherwise. If the ball drawn is white, what is the probability that it came from Urn A?

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya