The heights of soldiers are normally distributed if 11.51% of the soldiers an taller than 70.4 inches and 1.65 %. are shorter than 65.4 Inchess. Find the mean and Standard deviation for the date and heights of the soldiers

2

Step-by-step explanation:

mean = 67.6

Step-by-step explanation:

The height of the soldier are normally distributed. If 11.51% of the soldiers are taller than 70.4 inches

and 9.68% are shorter than 65.4 inches.

Find the mean and Standard Deviation for the data of height of soldiers.

[Given Zval(.8849)=1.2 and Zval (.9032)=1.3]

11.51 % are taller than 70.4 inches

=> 88.49% are smaller than 70.4

z score for .8849 = 1.2

z score =( value - mean)/standard deviation

1.2 =( 70.4 - mean)sd

1.2sd = 70.4 - mean

9.68% are shorter than 65.4 inches

90.32% are larger than 65.4 inches

-1.3 = ( 65.4 - mean)/sd

-1.3sd = 65.4 - mean

2.5sd = 5

sd = 2

1.2*2 = 70 - mean

mean = 67.6

there will be 35 boys in each team. : )

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.