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Find the difference

(1-5q)-(2.5s+8)-(0.5q+6)=

11q + 5s + 26

Step-by-step explanation:

((1-5q)-((25/10•s)+8))-((1/2•q)+6)

= ((1-5q)-((25/10•s)+8))-(q+12)/2

= ((1 - 5q) -  ((5/2 • s) +  8)) - (q + 12)/2

= ((1 - 5q) -  (5s + 16)/2 - (q + 12)/2

= (-10q - 5s - 14)/2 - (q + 12) /2

= -10q - 5s - 14  

= -1 • (10q + 5s + 14)

= 11q + 5s + 26

step-by-step explanation:

1

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204