Help me out and I will give you brainliest. =) Which best reflects Loyalists feelings during the Revolutionary War?
A. Great Britain has no right to pass laws affecting affecting the colonies
B. The colonist deserve a democratic from of government
C. Defeating the British is the only way to end slavery in the colonies
D. The colonies benefit from being part of the British empire

D. The colonies benefit from being part of the British empire

Step-by-step explanation:

I believe the correct answer would be C. the colonists benefit from being part of the British empire.

Step-by-step explanation:

This is because the Americans were classified as two different groups: Patriots and Loyalists. The Patriots were all for American freedom, they wanted to control their own future and didn't want to be bossed around by the British who were far overseas. The Loyalists were loyal to King George III and believed that there was no reason to want to separate because Great Britain was their protection from other unwanted nations.

man its nopq i just guessed and got it right so uhh

g00d lucc

step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )