Ive tried everything and still dont understand can you help?

13.896 kg

Step-by-step explanation:

Volume of Gold Bar = Area of [Trapezium x Length of Bar]

Length of Bar = 16 cm

Area of Trapezium = 2 × Area of Triangle + Area of Rectangle

Area of Triangle = 0.5 × 5 × 3 = 7.5 cm²

2 × Area of Triangle = 2 × 7.5 = 15 cm²

Area of Rectangle = 6 × 5 = 30 cm²

Area of  Trapezium = 15 + 30 = 45 cm²

Volume of Gold Bar = 45 × 16 = 720 cm³

Density of Gold = 19.3 g/cm³

Mass of Gold Bar = 720 × 19.3 = 13896 g = 13.896 kg

Mass of Gold Bar = 13.896 kg

Therefore the mass of the Gold Bar is: 13.896 kg (kilograms).

13.896kg

Step-by-step explanation:

First, find the volume of the trapezium.

Volume = area of cross-sectional area times the length (16cm)

[(a+b)/2] times height

(6+12)/2 x 5

(18/2) x 5

9 x 5

= 45 <-- area of cross section

45 x 16 = 720 cm^3 <-- volume

To find the mass, multiply volume times density

720 x 19.3 = 13 896g  = 13.896kg

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55/i dont know i do it for the points

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