The average number of points a basketball team scored for three games was 63 points. In the first two games they scored the same number of points which was 6 points more than they scored in the third game. Write and solve an equation to find the number of points the team scored in each game.

First Game: 65 points

Second Game : 65 points

Third Game : 59 points

Step-by-step explanation:

Average = sum of values/number of values

The number of values = 3, an d average = 63

63 = x/3

63 * 3 = x

189 = x

Now 189 is the sum of points over two games.

Their first two games are worth the same, so lets call that s +s = 2s

Their 3rd game is worth 6 less points than s, so s-6

let's add up all the terms:

2s + (s - 6) = 3s - 6

Solve:

3s - 6 = 189

3s = 195

s = 65

The first two games are worth 65, and the third game is worth 65 - 6 = 59.

-Chetan K

65, 65 and 59

Step-by-step explanation:

If represented by x and y, (2x+y)/3=63

So 2x+y=189

So if x=y+6

Put the value of x into the equation

2x + y = 189

2(y + 6) + y = 189

2y + 12 + y = 189

3y = 189 - 12

3y = 177

y = 177/3

y = 59

Therefore, x = y + 6 = 59 + 6 = 65

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

i have no clue at all sorry

step-by-step explanation: