1) A 60 cm length of wire is used to form a rectangle. The width of the rectangle is 3 cm longer than the height. Not all
the wire is used.
Find the range of values for the shortest side.

Step-by-step explanation:

here's a somewhat answer, and how to solve it

lets assume that all "60 cm wire is used to make a rectangle"

h = a

w = a + 3

the perimeter of the rectangle is

a + a + a + 3 + a + 3 = 60

4a = 54

a = 13.5

height = 13.5

width = 16.5

BUT, the problem says "not all the wired is used"

how much? 59? 58? 57 the lowest value for the shortes side is 1

h = 1

w = 1 + 3 = 4  

perimeter : 1 +4 + 4 + 1 = 6cm

if this is not good enough. please make a comment below to delete my answer

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

ian gonna lie that is way to much