Find the equation of the line that passes through (-1,2) and is perpendicular to y=1−2x. Leave your answer in the form ax+by=c Where a, b and c are integers.

Step-by-step explanation:

Hi there!

The equation of the line which passes through the point (-1,2) is (y-2) = m1 (X+1)(i). {using one point formula (y-y1) = m(x-x1)}

Again the given equation is: y= 1-2x

or, y= -2x+1(ii)

Comparing equation (ii) with y= mx+c, we get;

m2 = -2

Since the lines are perpendicular;

m1*m2 = -1

m1*(-2) = -1

Therefore, m1= 1/2.

Keeping the value of m1 in equation (I);

(y-2) = 1/2(x+1)

2y-4 = x+1

Therefore, the required equation is x-2y= -5.

Hope it helps!

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64