If a²+b²=8ab, determine (a+b) in terms of a and b

[The question's not wholly right! Since, (a+b) has a and b in it, it already is in terms of a and b. Here, we'll be representing (a+b) in terms of ab]

Step-by-step explanation:

We have the rules of indices, one of which is:

Indices are the powers, the numbers written as superscript in front of a variable or the numbers that come along with "^". It shows how many times a number is to be multiplied by itself.

In the question, we're provided with one equation, i. e.,

And, were asked to find out the value of (a+b) in terms of ab.

The above rule has variables that fit in the question efficiently!

So, instead of solving for (a+b), we'll be solving for (a+b)²,  then go for (a + b):

=> (a + b)² = (a² + b²) + 2ab

from eqn. (¡):

=> (a + b)² = 8ab + 2ab

=> (a + b)² = 10ab

taking under root on both the sides:

=> (a + b) =

That's the answer,  !

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi