If line AB is congruent to DE , b is the midpoint of AC and e is the midpoint of Df then BC is congruent to EF

two data sets with the same median will not have the same varaibility

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

the ratio would be 4: 3, the four being for jackson, and the three being not for him.