1. The function $f$ satisfies
\[f(\sqrt{x + 1}) = \frac{1}{x}\]for all $x \ge -1,$ $x\neq 0.$ Find $f(2)$.

2.
Let
\[f(x) = \frac{3x - 7}{x + 1}.\]Find the domain of $f$. Give your answer using interval notation.

3.
Let
\[f(x) = \frac{3x - 7}{x + 1}.\]Find the range of $f$. Give your answer as an interval.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

24

step-by-step explanation: