Mathematics, 05.10.2021 05:50, 20meansdd
Find the remainder when 9²-fix 2 is divided by 1-3 (x+3 (i) 3x+1 (0) 1SolutionLet p(x) = 9x ^ 2 - 6x + 2 When p(x) is divided by x-3, by Remainder Theorem, the remainder isR=P(3)=9(3)³-6(3)+2=65When p(x) is divided by x + 3 = x - (- 3) , the remainder isR=(-3)=9(-3)²-6(-3)+2=101 When pix) is divided by 3x+1, the remainder isWhen p(x) is divided by 1, the remainder is R =p(0)=9(0)³-6(0)+2=2
Answers: 1
Mathematics, 21.06.2019 22:00, LilFabeOMM5889
In δabc, m∠acb = 90°, cd ⊥ ab and m∠acd = 45°. find: a find cd, if bc = 3 in
Answers: 1
Mathematics, 22.06.2019 01:00, lolhgb9526
Sanderson is having trouble with his assignment. his shown work is as follows: − 3 7 7 3 = − 3 7 × 7 3 = − 21 21 = −1 however, his answer does not match the answer that his teacher gives him. complete the description of sanderson's mistake. find the correct answer.
Answers: 3
Mathematics, 22.06.2019 06:10, michaellagann2020
Asensitive measuring device is calibrated so that errors in the measurements it provides are normally distributed with mean 0 and variance 2.00. find the probability that a given error will be between -3 and 3.
Answers: 1
Find the remainder when 9²-fix 2 is divided by 1-3 (x+3 (i) 3x+1 (0) 1SolutionLet p(x) = 9x ^ 2 - 6x...
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