Mathematics, 05.10.2021 01:00, JeroMii

Let ∆(x) = |1+ sin²x cos²x 4sin2x |
|sin²x 1+co²x 4sin2x |
|sin²x cos²x 1+4sin2x|

The value of x (0 ≤ x ≤ π/x) for which ∆(x) is maximum, is equal to
(a) π/2
(b) π/6
(c) π/3
(d) π/4

Let ∆(x) =

|1+ sin²x cos²x 4sin2x ||sin²x 1+co²x 4sin2x ||sin²x cos²x 1+4sin2x|The value of x (0

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