When Isabella left her house in the morning, her cell phone battery was partially charged. Let BB represent the charge remaining in Isabella's battery, as a percentage, tt hours since Isabella left her house. The table below has select values showing the linear relationship between tt and B. B. Determine the percentage charge that Isabella's phone loses each hour.

5% each hour

Step-by-step explanation:

in 1.5 hours she loses 7.5% of battery

get the percentage of loss for a half hour.

divide 1.5 and 7.5 by 3.

That gives a loss of 2.5% for every half hour.

Which gives a loss of 5% percent an hour.

0.6

39mph

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752