Each side of a square is increasing at a rate of 6 cm/s. At what rate is the area of the square increasing when the area of the square is 16cm^2?

Solution: 48cm/s^2

Working:

A = s^2

Derivate s^2 (as it is area formula) which gives

dA/dt = 2s dL/dt

dL/dt = 6cm/s

Hence,

2(6) = 12

Side: 4cm

Hence,

dA/dt = (4)(12) = 48cm/s^2

Feel free to mark this as brainliest :D

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

i think the answer is b