I need help with this. -y^2+x^3-4x^3-6y^3+5-2x^3

Step-by-step explanation:

How to solve your problem

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y^{2}+x^{3}-4x^{3}-6y^{3}+5-2x^{3}

y2+x3−4x3−6y3+5−2x3

Simplify

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Combine like terms

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y^{2}+{\color{#c92786}{x^{3}}}{\color{#c92786}{-4x^{3}}}-6y^{3}+5{\color{#c92786}{-2x^{3}}}

y2+x3−4x3−6y3+5−2x3

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y^{2}{\color{#c92786}{-5x^{3}}}-6y^{3}+5

y2−5x3−6y3+5

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Rearrange terms

Solution

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-y^2-5x^3-6y^3+5

Step-by-step explanation:

Collect the terms

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)