Mathematics, 03.10.2021 16:00, jc95704816

In most of the previous examples there were only two terms. Extend your work with using the Distributive Law "backwards" and write the following as a product of binomials.
(a) x(x+2)+3(x+2)+4x(x+2)
(b) 2x(x-5)+3(x-5)+(x-1)(x-5)

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In most of the previous examples there were only two terms. Extend your work with using the Distributive Law "backwards" and write the following as a product of binomials. (a) x(x+2)+3(x+2)+4x(x+2) (b) 2x(x-5)+3(x-5)+(x-1)(x-5)

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In most of the previous examples there were only two terms. Extend your work with using the Distributive Law "backwards" and write the following as a product of binomials.
(a) x(x+2)+3(x+2)+4x(x+2)
(b) 2x(x-5)+3(x-5)+(x-1)(x-5)