2x+4y-2z=0 Need help getting x y and z

x = -2y + z

y = -1/2x + 1/2z

z = x + 2y

Step-by-step explanation:

x:

First, isolate the variable you want to solve for:

To isolate x, add the inverses of y and z to both sides of the equation.

2x + 4y - 2z = 0

2x - 2z = -4y

2x = -4y + 2z

To find x, divide both sides by 2:

2x = -4y + 2z

x = -2y + z

y:

First, isolate the variable you want to solve for:

To isolate y, add the inverses of x and z to both sides of the equation.

2x + 4y - 2z = 0

4y - 2z = -2x

4y = -2x + 2z

To find y, divide both sides by 4:

4y = -2x + 2z

y = -1/2x + 1/2z

z:

First, isolate the variable you want to solve for:

To isolate z, add the inverses of x and y to both sides of the equation.

2x + 4y - 2z = 0

4y - 2z = -2x

-2z = -2x - 4y

To find z, divide both sides by -2:

-2z = -2x - 4y

z = x + 2y

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: