Marcus is buying 10 gift bags for his birthday party. He will choose items to put
in the bags and then pay an additional
charge of $0.75 for the actual bag.
Marcus cannot spend more than $50,
Write and solve an inequality to find the
most Marcus can spend on the items for
each bag,

Show work

Step-by-step explanation:

Let cost of items for 10 bags be represented by x

Cost of 1 bag=$ 0.75

Cost of 10 bags=$ (0.75×10)

                        = $ 7.5

Total cost of 10 bags with items in them=$(7.5+x)

Marcus cannot spend more than $50.

i.e. 7.5+x≤50

Subtracting both sides by 7.5

x≤42.5

Most Marcus can spend for items in 10 bags=$42.5

Most Marcus can spend for items in 1 bag=$(42.5/10)=$4.25

Hence, most Marcus can spend on the items for each bag is:

$4.25

you can also find this on

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

answer: procent 54 wynosi 33,33%