Consider an object moving with velocity function v(t)=1t+3 for t≥0. Give a geometric argument to show that the distance d travelled between t=x and t=x+1, with x≥0, satisfies the inequality 1x+4

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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the answer to your question might be 45 degrees.

90+45=135

180-135=45