Solve the system of equations:
y = 2x - 4
y= x^2 - 4

correct question

y=2x -4

y=x²-4

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The two intersections would be (3, 10) and (-2, 0)

Step-by-step explanation:

To solve this system of equations, set the two equations equal to each other and solve for x.

2x + 4 = x² + x - 2

2x = x² + x - 6

0 = x² - x - 6

0 = (x - 3)(x + 2)

Now set the parenthesis equal to zero to get the x values.

x - 3 = 0

x = 3

x + 2 = 0

x = -2

Now we know the x values of each interception. We can find the y values by plugging into either equation.

y = 2x + 4

y = 2(3) + 4

y = 6 + 4

y = 10

y = 2x + 4

y = 2(-2) + 4

y = -4 + 4

y = 0

your answer is a

step-by-step explanation:

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step-by-step explanation:

most likely the answer is a.

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