PLEASE HELP I WILL MARK BRAINLIEST AND GIVE 59 POINTS
YES, 59

Given :-

∠C = 90°

CD is the altitude to AB.

∠A = 65° .

Solution :-

in Right angle ∆ABC , we have ,

→ ∠ACB = 90°

→ ∠CAB = 65° .

So,

→ ∠ACB + ∠CAB + ∠CBA = 180° (By angle sum Property.)

→ 90° + 65° + ∠CBA = 180°

→ 155° + ∠CBA = 180°

→ ∠CBA = 180° - 155°

→ ∠CBA = 25° .

Now, in ∆CDB ,

→ CD is the altitude to AB.

So,

→ ∠CDB = 90°

→ ∠CBD = ∠CBA = 25° .

So,

→ ∠CDB + ∠CBD + ∠DCB = 180° (Angle sum Property.)

→ 90° + 25° + ∠DCB = 180°

→ 115° + ∠DCB = 180°

→ ∠DCB = 180° - 115°

→ ∠DCB = 65° .

Now, in ∆ADC ,

→ CD is the altitude to AB.

So,

→ ∠ADC = 90°

→ ∠CAD = ∠CAB = 65° .

So,

→ ∠ADC + ∠CAD + ∠DCA = 180° (Angle sum Property.)

→ 90° + 65° + ∠DCA = 180°

→ 155° + ∠DCA = 180°

→ ∠DCA = 180° - 155°

→ ∠DCA = 25° .

Hence, from all above (Also image.) we get,

∠DBC = 25°

∠DCB = 65°

∠CDB = 90°

∠ACD = 25°

∠ADC = 90° .

Answer

2=35 3=45 4=16 5=27

Step-by-step explanation:

if its wrong im really truly honestly sorry i tried my best

can i see the following ?

step-by-step explanation:

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: