The sum of 4 consecutive integers is 38. What is the greatest of these integers?

11

Step-by-step explanation:

let the consecutive integers be

n, n + 1, n + 2, n + 3 , then

n + n + 1 + n + 2 + n + 3 = 38 , that is

4n + 6 = 38 ( subtract 6 from both sides )

4n = 32 ( divide both sides by 4 )

n = 8

n + 1 = 8 + 1 = 9

n + 2 = 8 + 2 = 10

n + 3 = 8 + 3 = 11

The greatest of the integers is 11