Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards without replacement from a standard deck. If both cards are clubs, your friend will pay you $12. Otherwise, you have to pay your friend $3. What is the expected value of your bet? Round your answer to two decimal places. Losses must be expressed as negative values.

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to

8x - 61 = 17add 8x = 88x = 11 (cannot be proven)4(3(7) - 8) = 524(21 - 8) = 5284 - 32 = 52 (proven)

The answer is -1,19,39,59