In an arithmetic sequence, a1=5 and a10=19. find a6

In an arithmetic sequence, the nth term, an, is given by the formula an = a1 + (n-1)d, where d is the common difference (the difference between consecutive terms).

So, a10 = a1 + 9d = 10 and a8 = a1 + 7d = -1

We have the system of equations:

a1 + 9d = 10

a1 + 7d = -1

Subtracting, we get 2d = 11. So, d = 5.5 and a1 = -39.5.

Therefore, a6 = a1 + 5d = -39.5 + 5(5.5) = -12

Explanation

Pls mark as brainliest

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b