Can someone solve for y and z?

y = 12°

z = 120°

(you didn't ask, but x = 52°)

Step-by-step explanation:

110° = 2x+6

(corresponding angles says this is true)

104° = 2x

x = 52°

Then:

(5y + 10) + (2x + 6) = 180°

(5y + 10) + (2(52) + 6) = 180°

5y + 10 + 104 + 6 = 180°

5y + 120 = 180°

5y = 60°

y = 12°

Last:

5y + 10 = z - 50

(vertical angles prooves this is true)

5(12)+10 = z - 50

60 + 10 = z - 50

70 = z - 50

120 = z

z = 120°

Hope this helps and is correct, have a nice day! :D

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497