Factored form of 2x^2+x-3 must show work

(2x+3)(x - 1)

Step-by-step explanation:

Since there is no common number to factor by we must approach this problem differently:

Step 1:

Multiply leading coefficient (2) by the constant term (-3)

2 x -3 = -6

Step two:

Find two numbers that multiply to -6 but add to the middle coefficient (1).

You should find these numbers to be 3 and -2

Step 3:

Replace 1x in the equation with your found numbers

2x^2 - 2x + 3x - 3

Step 4:

Take out the greatest common factor from the first two numbers, and the last two numbers.

For 2x^2 - 2x the greatest common factor would be 2x

For 3x - 3 the greatest common factor would be 3.

Step 5:

Factor out the found common factors

2x(x-1) + 3(x-1)

The values inside the bracket should be the same.

Step 6:

Factor out (x-1)

(x - 1)(2x + 3)

Therefore the factored form is (2x + 3)(x - 1)

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl