A line that is perpendicular to the graph of 3x+2y=6 and contains the point (6,-3)

y = (-2/3)x +1

Step-by-step explanation:

The standard equation of a line is: y=mx+b where m-is the slope, and b-is the y intercept. Rewrite the given equation in standard form.

3x+2y = 6

     2y = 3x+6

        y= (3/2)x+3

So the given equation has the slope m =3/2 and y-intercept= 3

A line ⊥ to the given line will have the slope negative reciprocal so the line is

        y= (-2/3 )x +b

To find b will substitute the given point (6,-3) in the new found equation

       -3= (-2/3 )6 +b

       -3= -4 +b

  -3+4 = b

        1 = b

The equation of the line that is perpendicular to the graph of 3x+2y=6 and contains the point (6,-3) is y = (-2/3)x +1

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|