Mathematics
Mathematics, 26.09.2021 14:00, shyann78

Describe and correct the error to solving the equation The two solutions are extraneous, so there is no solution.

x=βˆ’43 is an extraneous solution, so the solution is x=βˆ’2.

x=βˆ’2 is an extraneous solution, so the solution is x=βˆ’43.

The two solutions have the wrong sign, so the solutions are x=2 and x=43.


Describe and correct the error to solving the equation

The two solutions are extraneous, so there

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