Jenny runs five miles a day with an absolute error of three quarters of a mile. Which absolute value equation gives the minimum and the maximum miles that Jenny runs each day. A) |m+5|=0.75 B) |m+5|=-0.75 C) |m-5|=0.75 D) |m-5|=-0.75

5| ≤ ¾

Step-by-step explanation:

We are told that Jenny runs five miles a day.

Also, we are told that he has an absolute error value of ¾ mile.

So, it means the true distance he ran could range from between (5 + ¾) to (5 - ¾) miles.

C) |m-5|=0.75

Step-by-step explanation:

|m-5|=0.75

if m≥5     m-5 = 0.75         m = 5.25   ...  maximum

if m<5     -(m-5) = 0.75      -m + 5 = 0.75         m = 4.25    ... Minimum

|m-5| ≥ 0   D is not the option

8121 because

130,000 divided by 16 is 8121

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)