X tends to 0 sinax-sinbx upin x

Solution

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x→0

lim

sinbx

sinax

=

x→0

lim

(

bx

sinbx

)×bx

(

ax

sinax

)×ax

=(

b

a

)×

lim

x→0

(

bx

sinbx

)

lim

x→0

(

ax

sinax

)

=(

b

a

)×

1

1

=

b

a

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

i believe it’s 165 because if u add 137 and 58 u get 195 and then subtract that from 360 and there’s ur answer