Lesson 7 Using Distributive Property Area Assignment.
pls help

Step-by-step explanation:

1) 3*7

2) a*4

3) m*m

4) (4*x)+(4*1)

5) (7*d)+(7*4)

6) (y*y)+(y*3)

7) 1+x

8) d+4

9) y+3

11) Area as Sum: 7d+28, Area as Product 7(d+4)

12) Area as Sum: y(y)+3, Area as Product y(y+3)

13) 5m+10

14) 8y+16

15) -3m-12

16) a^2+3a

17) h^2 2h

18) 2m^2+8m

19)-2z-16

20)-4x^2-40

21) (12x)(60), Area as Sum: 12x+60, Area as Product 12(x+60)

22) (x)(4), Area as Sum: 5x+20, Area as Product 5(x+4)

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d