Two numbers are consecutive integers. Six times the smaller integer equals three times the greater integet. Find the integers?

1 and 2

Step-by-step explanation:

let the consecutive integers be n and n + 1 , then

6n = 3(n + 1)

6n = 3n + 3 ( subtract 3n from both sides )

3n = 3 ( divide both sides by 3 )

n = 1

and n + 1 = 1 + 1 = 2

The integers are 1 and 2

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3