What is the equation of a line parallel to y=-3x+5 that passes through point (6, 8)

5y = 6x + 4

Step-by-step explanation:

from the given equation we have to calculate y-intercept and the slope.

y= -3x+5

when x=1

y=-3(1)+5

y=-3+5 = 2

.: slope = (y₂-y₁)/(x₂-x₁)

slope= (8-2)/(6-1)

slope= m= 6/5

now the intercept

y = mx+b

8 = (6/5)(6) +b

8=36/5 + b

b = 8 - 36/5

b = (8×5 - 36)/5

b= (40-36)/5

b = 4/5

.: the slope-intercept formula

y=mx+b

y=(6/5)x + 4/5

y = (6x +4)/5

5y = 6x+4

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.