Suppose that quiz scores in a beginning statistics class have a mean of 7.5 with a standard deviation of 0.4. Using Chebyshev's Theorem, state the range in which at least 88.9% of the data will reside. Please do not round your answers.

Chebyshev's theorem says that the probability that a random variable differs from its mean by some multiple of the standard deviation is bounded below as

Solve for k :

Then the theorem says

which is to say that 88.9% of the data will fall in the interval

or roughly corresponding to scores between 7.076 and 7.924.

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all