What r the answers, please help me, thanks :)​

Over the interval [2, 4], the local minimum is -8.

Over the interval [3, 5], the local minimum is -8.

Over the interval [1,4], the local maximum is 0.

Step-by-step explanation:

For the first option it is not a local minimum but rather a local maximum

In the second interval 3.4,-8 is the smallest value in that interval, so that's true

The same applies with the next interval

The fourth interval 1,4 has a local max at two spots; 2,0, 4,0 so that's true

and lastly in this interval 3,5 the reason this is false is because after x=4 the

graph continues and 4,0 is not a local max as the range ends at x=5

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.