![{ \tt{ \frac{1}{16} \div \sqrt[3]{2} = {2}^{n} }} \\ \\ { \tt{\frac{1}{16} \times \frac{1}{ {2}^{ \frac{1}{3} } } = {2}^{n} }} \\ \\ { \tt{ \frac{1}{ {2}^{4} } \times \frac{1}{ {2}^{ \frac{1}{3} } } = {2}^{n} }}](/tpl/images/2470/5751/39290.png)
Work out the value of "n"
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Answers: 3
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