find two integers such that their mean is 15 and 2 less the larger number is thrice the smaller number.​

Step-by-step explanation:

So we first need to assign letters to represent the numbers.

Let 'a' be the larger number and 'b' the smaller.

Now we can use this to write equations that we can solve simultaneously to find both 'a' and 'b'.

according to the question:

(a + b) ÷ 2  = 15   [1]

a = 3b              [2]

We can substitute 'a' in [2] for 'a' in [1]

⇒ (3b + b) ÷ 2  = 15

⇒    4b ÷ 2 = 15

⇒            b  = ¹⁵/₂

We can plug this value of b into equation [2] to solve for a

⇒  a = 3 (¹⁵/₂)

⇒  a = ⁴⁵/₂

the barter

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet