A fruit company delivers its fruit in two types to boxes: large and small. A delivery of 3 boxes and 8 small boxes has a total weight of 178 kilograms. A delivery of 5 large boxes and w small boxes has a total weight of 120 kilograms . How much does each type of box weigh?

Large box: 18.25

small box 15.5

Step-by-step explanation:

2L + 3S = 83

4L + 8S = 197

Multiplies the top equation by -2.

-4L + -6S = -166

4l  + 8S = 197

Adding them together...

2S = 31

S = 31/2 = 15.5

Plugging into the first equation:

 2L + 3S = 83

 2L + 3(15.5) = 83

2L + 46.5 = 83

2L = 83 - 46.5

2L = 36.5

L = 36.5/2 = 18.25

check:

2L + 3S = 2(18.25) + 3(15.5) = 36.5 + 46.5 = 83

4L + 8S = 4(18.25) + 8(15.5) = 73 + 124 = 197

The Large box weighs 18.25

The small box weighs 15.5

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

43

step-by-step explanation: