Mathematics, 19.09.2021 20:00, zay179

F(1) = 6
f(n) = f(n – 1) – 5
for integer values of n>1

Answers: 2

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F(1) = 6
f(n) = f(n – 1) – 5
for integer values of n>1...

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F(1) = 6 f(n) = f(n – 1) – 5 for integer values of n>1

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F(1) = 6
f(n) = f(n – 1) – 5
for integer values of n>1